Re: Can't use variadic arguments to functions that use templates

[Jesse Phillips]

On Tuesday, 23 July 2013 at 14:03:01 UTC, JS wrote:
I don't think you understand(or I've already got confused)...
I'm trying to use B has a mixin(I don't think I made this 
clear). I can't use it as a normal function. e.g., I can't seem 
to do mixin(B(t)). If I could, this would definitely solve my 
problem.

I'll stick with the reduced example, maybe you can apply it to 
the real world:

   template B(T...) {
      string B(T b) {
         string s;
         foreach(i, Type; T)
            s ~= Type.stringof ~ " " ~ b[i] ~ ";\n";
         return s;
      }
   }

   void main() {
      enum forced = B("x", "a", "b");
      pragma(msg, forced);
      mixin(forced);
   }