On 2013-08-12 17:49, JS wrote:
Sorry but this doesn't work. b is a B, not an A.try I a = new A; I b = new B;
Right, forgot about the interface. -- /Jacob Carlborg
On 2013-08-12 17:49, JS wrote:
Sorry but this doesn't work. b is a B, not an A.try I a = new A; I b = new B;
Right, forgot about the interface. -- /Jacob Carlborg