On Oct 1, 2013, at 7:10 PM, Nick Sabalausky <seewebsitetocontac...@semitwist.com> wrote:
> I thought variable.init was different from T.init and gave the value of
> the explicit initializer if one was used. Was I mistaken?:
>
> import std.stdio;
> void main()
> {
> int a = 5;
> writeln(a.init); // Outputs 0, not 5
> }
I think it used to work roughly this way but was changed… um… maybe 2 years ago?
