On 12/08/2013 12:24 AM, seany wrote:
> std.algorithm.splitter seems to return all its return values as a type
> "Result", without quotes, and i dont not seem to be able to cast it to
> string[] or int[] with cast(string[]) ( or even cast (string) - i tried
> that too).
>
> I tried to use a function
>
> void function(T, R)(T arr, out R output)
> {
>
> foreach(elem; arr)
> {
> output ~= elemM
> }
> }
>
> i have an occasion where R is int[], and one where it is string[]; and
> but it says, that int can not be appended to string[], and string can
> not be appended to int[], and compilation fails.
>
> Nonetheless removing either of the occasions, solves it.
>
> how to deal with this Result type?
Many other algorithms return Result, which are independent from each
other. :) (Lookup "Voldemort types".)
Such types are just lazy ranges. When you eagerly need an actual array
of the elements, call std.array.array on Result:
import std.array;
import std.algorithm;
void main()
{
auto input = "hello world";
auto splittedWords = input.splitter(' ').array;
static assert(is (typeof(splittedWords) == string[]));
}
Ali
