Thanks!
auto app = appender(&unitlist);
Ah, I'd been wondering if there was something like this. But why
does it need unitlist's address? (Assume & has the same meaning
as in C and C++.)
This one seems like it should be unitlist.filter!(x => x.any!(y
=> s==y)).array();
Oh. Duh. But what is the .array() at the end doing? Allocating a
new array for the results of the filter, since it's basically
just a lazily computed range rather than actual storage for the
results?
foreach(s; squares){
peers[s] = remove(chain(units[s]), s); \\line 41
}
This one I don't understand. chain(units[s]) ? That's the same
as units[s]. remove() returns a range, in this case string[][].
I'm just trying to match what the python code was doing. In that
case the line
peers = dict((s, set(sum(units[s],[]))-set([s]))
for s in squares)
was using sum to concatenate a bunch of lists together and then
remove the element. But I miscounted the parentheses and didn't
notice the '-' was after the concatenated lists were tured into a
set. The following code appears to do what I want, but the string
temporary and appender are a bit ugly. Any suggestions on getting
rid of them?
foreach(s; squares){
string[] tmp;
auto app2 = appender(&tmp);
foreach(t; units[s]) {app2.put(t);}
peers[s] = tmp.sort().uniq().filter!(a => a!=s).array();
}
