On Sunday, 26 January 2014 at 13:05:55 UTC, Stanislav Blinov
wrote:
On Sunday, 26 January 2014 at 12:50:05 UTC, matovitch wrote:
Hello !
I got a problem which I'm sure can be solved by a smart one
liner. I would like to obtain the term by term product of a
given range by the infinite cyclic range cycle([1,-1]). How
can I do that ?
dpaste seems to be somewhat slow.
import std.range;
import std.algorithm;
import std.stdio;
void main() {
auto myRange = iota(0,10);
foreach(e; myRange.zip(cycle([1,-1])).map!(a => a[0]*a[1]))
writeln(e);
}
Like this?
Exactly ! I just found this solution too. Thanks.
