On Saturday, 22 March 2014 at 22:54:15 UTC, captaindet wrote:
pls see example code below.
the two 'test' templates work fine by themselves. if, however,
in the same module, the eponymous template does not work
anymore. instead the compiler seems to try instantiating the
variadic template.
a) why? for how i understand it, this should not happen as
o they have very different signatures, i.e. completely
incompatible argument lists ( zero vs >1 arguments)
o the string parameter is more specialized than the take-all
tuple
b) how can i make it work?
cheers,
det
CODE:
=====
import std.stdio;
// cannot be used with function arguments
template test(string str ){
enum test = "template 'test' used with "~str;
}
// cannot be called with less than 2 function arguments
string test (T ...)( T strs )
if( 1<strs.length )
{
return "templated function 'test' called with "~strs[0]~" and
"~strs[1];
}
// enum epo = test!"one"; // use eponymous template
// if commented in:
// Error: tuple T is used as a type
// in line 9 = string test (T ...)( T strs )
enum vari = test("two", "three"); // use templated/variadic
function
void main(string[] args)
{
// writeln( epo );
writeln( vari );
}
Looks like a bug to me.
By the way, the variadic template is eponymous, too: The template
declares a function with the same name.
