Re: Getting a class' name, but not fully qualified?

[w0rp]

You could do the following.

class Klass {
    static class SubKlass {
    }
}
string baseName(ClassInfo classinfo) {
    import std.array;
    import std.algorithm : countUntil;
    import std.range : retro;

    string qualName = classinfo.name;

    size_t dotIndex = qualName.retro.countUntil('.');

    if (dotIndex < 0) {
        return qualName;
    }

    return qualName[$ - dotIndex .. $];
}

string classBaseName(Object instance) {
    if (instance is null) {
        return "null";
    }

    return instance.classinfo.baseName;
}

void main(string[] argv) {
    import std.stdio;

    writeln(Klass.classinfo.baseName);
    writeln(Klass.SubKlass.classinfo.baseName);

    Object x = new Klass();
    Object y = new Klass.SubKlass();

    writeln(x.classBaseName);
    writeln(y.classBaseName);
}

The above won't result in any extra allocation and there are two 
functions so you could find a class name both at compile time and 
a runtime without too much trouble.