On 06/12/2014 01:36 PM, Andrew Edwards wrote:
> void foo() {}
> alias bar = foo();
>
> Am I just misunderstanding what is meant by types?
Seems to be an old behavior. That does not compile with 2.066:
Error: function declaration without return type. (Note that constructors
are always named 'this')
The following compiles though:
alias bar = foo;
I stand corrected: alias works not only with types but with symbols as
well. I was right about the original code though: "Aliases cannot be
used for expressions".
Ali
