On Thursday, 18 September 2014 at 06:09:54 UTC, Algo wrote:
void main()
{
import std.utf;
decode("dlang", 1);
}
Error: template std.utf.decode cannot deduce function from
argument types !()(string, int), candidates are:
D:\msc\D\dmd2\windows\bin\..\..\src\phobos\std\utf.d(924):
std.utf.decode(S)(auto ref S str, ref size_t index) if
(!isSomeString!S && isRandomAccessRange!S && hasSlicing!S &&
hasLength!S && isSomeChar!(ElementType!S))
D:\msc\D\dmd2\windows\bin\..\..\src\phobos\std\utf.d(942):
std.utf.decode(S)(auto ref S str, ref size_t index) if
(isSomeString!S)
why doesn't "decode(S)(auto ref S str, ref size_t index) if
(isSomeString!S)" correspond?
I was having same issue a while ago. But I realized I was using
function in the wrong way with string type and passing a size_t
in the 2th argument. You can see use of decode(val, size) in the
standard library but call it in your code result in an error.
it worked:
string s = readText("file");
decode(cast(ubyte[]) s);
I'm not sure why you're trying to pass a string literal as
argument because it does need a memory location to change to new
memory location, where bytes skiped end. That's why it does use
ref.
