On 03/16/2015 11:28 AM, Suliman wrote:
> difference between:
> auto theTask = task(&someFunction);
> and:
> auto theTask = task!anOperation();
tl;dr - Prefer task!anOperation() unless you can't. :)
task() is flexible enough to take what to execute either as a function
(or delegate) pointer (task(&someFunction)) or as a template parameter
(task!anOperation).
The template method is more flexible because it can take anything that
can be executed. For that reason, I would prefer task!anOperation.
However, because it is a template parameter, the Task template instances
that are generated would not have the same type (even though two
functions have the same signature). This would e.g. prevent you from
putting two Task instances in an array:
import std.parallelism;
void foo()
{}
void bar()
{}
void main()
{
auto tasks = [ task!foo(), task!bar() ]; // COMPILATION ERROR
}
Error: incompatible types for ((task()) : (task())): 'Task!(foo)*' and
'Task!(bar)*'
So, you would have to give the function as a pointer:
auto tasks = [ task(&foo), task(&bar) ];
However, this overload actually do the same thing behind the scenes and
calls task!run(myFunc) behind the scenes (run() is a function template
defined in parallelism.d).
Ali
