On 03/24/2015 09:56 AM, matovitch wrote:
> just to be clear :
>
> void Bar(T : Foo)(T t){
> }
That means "if T can implicitly be converted to Foo".
>
> is the same as
>
> void Bar(T)(T t) if (is(T == Foo)){
> }
That means "if T is exactly Foo".
> and it is checked only at compile time ?
Yes to both.
Ali
