On Sunday, 12 April 2015 at 11:49:19 UTC, Baz wrote:
Hi,
while variable declarations work in list:
uint a,b,c;
function parameters declarations don't:
void foo(uint a,b,c);
Because of this, function declarations are sometimes super-wide.
(despite of the fact that:
http://www.brainyquote.com/quotes/quotes/a/alanperlis177279.html)
In the previous example, we could imagine that once a type
defined, it'd valid until a new one appears (until a
"redefinition" / an "override").
Is there anything in the grammar that prevents this syntax ?
Thx.
void foo(int a, b);
Is `b` a second int argument, or is there a user defined type
named `b` and the second argument is nameless of type `b`?
