On Wed, 10 Jun 2015 20:22:17 +0000 Adel Mamin via Digitalmars-d-learn <digitalmars-d-learn@puremagic.com> wrote:
> ubyte[5] a = 0xAA; // Fine. Five 0xAA bytes. > auto a2 = new ubyte[5]; // Fine. Five 0 bytes. > Now, let's say, I want to allocate an array of a size, derived at > run time, and initialize it to some non-zero value at the same > time. What would be the shortest way of doing it? import std.stdio; struct Ubyte(ubyte defval) { ubyte v = defval; alias v this; } void main() { auto a2 = new Ubyte!(0xAA)[5]; writeln(a2); }