On 7/11/15 12:57 PM, flamencofantasy wrote:
On Thursday, 9 July 2015 at 15:14:43 UTC, Binarydepth wrote:
This is my code :
import std.stdio : writeln, readf;
void main() {
int[3] nums;
float prom;
foreach(nem; 0..2) {
writeln("input a number : ");
readf(" %d", &nums[nem]);
prom+=nums[nem];
}
writeln(prom/3.0);
}
I get prompted two times for a number and I then get NAN out of nowhere.
foreach(nem; 0..3)
that is a good catch, if the purpose is to fill in all 3 nums elements.
Note, a future-proof version would say:
foreach(nem; 0..nums.length)
A more d-idiomatic way is to say:
foreach(ref nem; nums)
And then use nem anywhere you see nums[nem]
-Steve