Sorry, the forum as stripped my answer. Here is the full version:
On Friday, 6 November 2015 at 19:26:50 UTC, HeiHon wrote:
Am I using std.utf.decode wrongly or is it buggy?
It's obviously used wrongly, try this instead:
import std.utf, std.stdio;
---
dstring do_decode(string txt)
{
dstring result;
try
{
size_t idx;
writeln("decode ", txt);
while (true)
{
result ~= std.utf.decode(txt, idx);
if (idx == txt.length) break;
}
}
catch(Exception e)
{
writeln(e.msg, " file=", e.file, " line=", e.line);
}
return result;
}
void main()
{
writeln(do_decode("abc"));
writeln(do_decode("Ã¥bc"));
writeln(do_decode("aåb"));
}
---
Additionally to what's been said in the other answers there was
also another error:
the `for()` loop was working on code points while there are
possibly less code units in `txt`. So instead you can use an
infinite loop and break when `txt` is decoded.
Alternatively you could also use std.range primitives to decode,
which can be considered as a more idiomatic way of doing things,
e.g:
---
import std.utf, std.stdio, std.range;
dstring do_decode(string txt)
{
dstring result;
try
{
size_t idx;
writeln("decode ", txt);
while (true)
{
if (txt.empty) break;
result ~= txt.front;
txt.popFront;
}
}
catch(Exception e)
{
writeln(e.msg, " file=", e.file, " line=", e.line);
}
return result;
}
void main()
{
writeln(do_decode("abc"));
writeln(do_decode("Ã¥bc"));
writeln(do_decode("aåb"));
}
---
because `front` auto decodes it argument.
To finish, a hint: you can use the unit tests found in phobos to
learn how to use a particular function. Usually there are more
than the one put as ddoc.
