Re: Unable to call each on a lockstep range containing 2 or more ranges

[John Colvin via Digitalmars-d-learn]

On Wednesday, 18 November 2015 at 14:11:45 UTC, maik klein wrote:

On Wednesday, 18 November 2015 at 13:51:59 UTC, John Colvin wrote:

On Wednesday, 18 November 2015 at 12:20:42 UTC, maik klein wrote:

[...]

I think this is a bug, please report it at issues.dlang.org and perhaps there will be an explanation or it will be fixed.

In the mean time, something like this should work:

  auto arange2 = zip(ai[],ai1[],ai2[]);

  arange2.each!((t) => writeln(t[0], t[1], t[2]));
  // or if you really must have the names:
  arange2.each!((t) => (a,b,c){ writeln(a, b, c); }(t.expand));

Thanks, but the problem I have with zip is that it doesn't work with "ref".

for example

auto arange3 = zip(ai[],ai1[],ai2[]);
foreach(ref a; arange3){
  a[0] = 42;
}
Won't change anything. Is this another bug?

Unfortunately, yes: https://issues.dlang.org/show_bug.cgi?id=10541

Note that

while(!arange3.empty)
{
    arange3.front[0] = 42;
    arange3.popFront();
}

should work as expected.