On Saturday, 5 December 2015 at 22:05:11 UTC, anonymous wrote:
On 05.12.2015 22:59, Quentin Ladeveze wrote:
---
import std.conv;
string s = "1B2A";
int value = parse!int(s[0..2], 16); //template std.conv.parse
cannot
deduce function from argument types !(int)(string, int)
---
Does someone have an idea of why it happens ? The version of
parse that
is used here is :
---
std.conv.parse(Target, Source)(ref Source s, uint radix) if
(isSomeChar!(ElementType!Source) && isIntegral!Target &&
!is(Target ==
enum))
---
And I can't see which template constraint is not respected
when I call
it with a slice.
It's the `ref` part. A slice expression cannot be passed in a
ref parameter. You can use std.conv.to instead or assign the
slice to a variable first.
Thank you for your quick answer, learned something today :)
