On Monday, 21 December 2015 at 09:44:20 UTC, Shriramana Sharma
wrote:
Hello. I want to define a template specialization using traits:
import std.stdio, std.traits;
void func(T)(T t) { writeln(1); }
void func(T)(T t) if(isIntegral!T) { writeln(2); }
void main()
{
func(1);
}
But I'm getting an error saying that the called function
matches both. If it were a single type, I know I have to put
the specialization as in:
void func(T: int)(T t) { writeln(2); }
and that works, but how to make it more generic than that?
void func(T)(T t) if(!isIntegral!T) { writeln(1); }
void func(T)(T t) if(isIntegral!T) { writeln(2); }
:)
