On Saturday, 2 January 2016 at 10:04:47 UTC, Shriramana Sharma
wrote:
import std.stdio;
union EarthLocation
{
struct { immutable double lon, lat, alt; }
double[3] data;
}
void main()
{
EarthLocation d = {data: [4, 5, 6]};
writeln(d.data);
d.data = [1, 2, 3];
writeln(d.data);
}
I get the output:
[4, 5, 6]
[1, 2, 3]
I thought the promise of `immutable` was: never changes,
whether via this interface or otherwise. How does then the
above work?
Using DMD 2.0.69.2 on Kubuntu 64 bit.
You are manually breaking immutable by making a union of
immutable and mutable data and then writing to the mutable
reference. This is roughly equivalent to casting away immutable
and then writing to the reference. It's a bug in your code.
All references to the same data should be
1) either immutable or const
or all the references should be
2) either mutable or const (assuming the data was never
immutable).
Anything else is dangerous.
