Re: link to C++ function in a namespace whose name is a D keyword

[Ali Çehreli via Digitalmars-d-learn]

On 01/06/2016 10:35 AM, Carl Sturtivant wrote:
Hello,
 From D I want to call e.g.

/* C++ prototype */
namespace ns {
     int try(int x);
}

without writing a C or C++ wrapper.

Presumably the following D doesn't work, because it doesn't mangle the
name as if it's in the namespace ns.

pragma(mangle, "try") extern(C++, ns) int try_(int x);

So how to I get correct mangling here?


This looks like an oversight to me. I tried the following workaround but 
it uses D mangling scheme:

import core.demangle;

// PROBLEM: No way of saying "mangle C++ name".
pragma(mangle, mangle!(int function(int))("ns::body"))
extern(C++, ns)
int body_(int x);

void main() {
    assert(ns.body_(42) == 42);
}

And yes, 'try' is a C++ keyword as well; so I moved to 'body. :)

Ali