On Sunday, 17 January 2016 at 10:43:55 UTC, Sean Campbell wrote:
On Sunday, 17 January 2016 at 10:34:19 UTC, locco wrote:
Hi :)
I found this example:
======================================================================
import std.file: write;
import std.string: representation;
void main()
{
char[] data = "Test data.\n".dup;
// Create an ArchiveMember for the test file.
ArchiveMember am = new ArchiveMember();
am.name = "test.txt";
am.expandedData(data.representation);
// Create an archive and add the member.
ZipArchive zip = new ZipArchive();
zip.addMember(am);
// Build the archive
void[] compressed_data = zip.build();
// Write to a file
write("test.zip", compressed_data);
}
======================================================================
But i cound't find example code for binary file.
How can i make ArciveMember for binary file?
std.zip dosen't discriminate against text and binary files
files.
p.s. remember to import std.zip
================================================================================
import std.stdio;
import std.file:write,getSize;
import std.string: representation;
import std.zip: ArchiveMember, ZipArchive;
void main() {
auto stream = File("example.jpg", "r+");
auto inbytes = new ubyte[ cast(uint)getSize("example.jpg") ];
stream.rawRead(inbytes);
auto zip = new ZipArchive();
ArchiveMember ae = new ArchiveMember();
ae.name = "example_.jpg";
ae.expandedData( inbytes );
zip.addMember(ae);
void[] compressed_data = zip.build();
write("test.zip", compressed_data);
}
================================================================================
I made this, work fine. But i guess it wasn't nice solution.
Right?
