On 2/19/16 8:53 AM, Jay Norwood wrote:
On Friday, 19 February 2016 at 07:59:29 UTC, Jonathan M Davis wrote:
.. Or you could do something really wonky like
auto arr = new int[][2][](5);
which would be a dynamic array of length 5 which holds static arrays
of length 2 which hold dynamic arrays which are null.
In my case, int [1][][1] ub;, there is only one dynamic dimension, but
if I try to use .length to change the length, ub.length = 3, the
compiler doesn't like that.
Try ub[0].length = 3. You are trying to change the length on one of the
static arrays.
If you had more than 1 as a static dimension, then you would have to
change the length of *each* of the elements.
Arrays in D, are actually quite simple. Any time you see:
T[]
It's a dynamic array of T. Any time you see:
T[N]
Where N is a compile-time integer, it's a static array of T.
So dissecting your type:
int[1][][1]
So the outer-most T is int[1][]. You have a single instance of this, in
a static array.
At the next level, T is int[1], where you have a dynamic array of these.
Finally, at the 3rd level, T is int, you have a single element in a
static array of int.
-Steve
