Re: inout and templates don't mix...

[Ali Çehreli via Digitalmars-d-learn]

On 03/23/2016 02:31 PM, cy wrote:

> struct Someop(Type) {
>    Type thing;
>    void foo() {
>      thing.bar();
>    }
> }
>
> struct Foo {
>    void bar() {
>      import std.stdio: writeln;
>      writeln("bar");
>    }
> }
>
> struct Bar {
>    void thingy(inout(Foo) foo) inout {
>      auto op = Someop(foo);
The following is a workaround for this example:

      auto op = Someop!Foo(foo);

I'm not sure whether Someop's implicit constructor should take part in 
deducing Someop's Type template parameter.

Ali