On Wednesday, 13 April 2016 at 16:58:34 UTC, Vladimir Panteleev
wrote:
On Wednesday, 13 April 2016 at 11:36:07 UTC, Mithun Hunsur
wrote:
Yeah, that also works; you have to define a symbol (if you
don't have one you can already use) in order to get to it, so
it's a little wasteful. Still useful to know, though!
No, it's not necessary. You should be able to walk the chain of
__traits(parent) by starting with a local symbol, e.g. a lambda
predicate.
Have a look at std.traits.moduleName which does most of the
work.
Aha! That is a _very_ clever trick. :) For everyone else:
__traits(parent, {});
The {} is a lambda predicate instantiated in the current scope
(i.e. module scope); getting the parent of that gets you the
module. If you wanted to generalise that, you could walk up the
parent chain like Vladimir says - but this is perfect for my
uses. Thanks again!
