On Tuesday, 19 July 2016 at 15:36:42 UTC, Lodovico Giaretta wrote:
As you have to do `isTuple!(T[0])`, you also have to do `x[0].expand`. That's because T... works "as if" it was an array of types, and x, being of type T, it works "as if" it was an array of values. So you have to use an index in both cases.
You can find this out from the error, which says that you can't expand an object of type `(Tuple!(int, int))`. Note the surrounding parenthesis: they tell you that what you have is not a Tuple, but an AliasSeq whose only member is a Tuple. If you do `[0]` on it, you obtain the correct type, i.e. `Tuple!(int, int)`, without the parenthesis.
