On Wednesday, 21 September 2016 at 08:21:29 UTC, Basile B. wrote:
On Wednesday, 21 September 2016 at 01:34:06 UTC, Nicholas
Wilson wrote:
On Tuesday, 20 September 2016 at 12:35:18 UTC, Basile B. wrote:
[...]
So if we rearrange and take the logs of both sides and divide
by c we get
2*log(1-y)/c = log(1-2^(-2/c))
and then that we have one occurrence of c on each side do an
iterative back substitution to find the intersection given
that you know for y=0.5 ,c = 2.
We used this method for finding voltages and currents in
circuits with semiconductors.
Y is a floating point value. I think I'm gonna make a LUT for
let's say 100 values to find the initial range where the result
stands.
What does Y being float have to do with this? LUT is a good idea,
a round number like 64 or 128 (or even 32) is probably better.
then do
g = 2*log(1-y);//constant
c(n+1) = g/log(1-2^(-2/c(n)))
where c(1) is a guess from the LUT.
the iteration should converge very fast.
