Re: Instantiating a class with different types at runtime

[Marduk via Digitalmars-d-learn]

On Sunday, 27 November 2016 at 21:06:58 UTC, ag0aep6g wrote:

Turn Example into a template, and add a free function for nice construction:

----
class Example(Type_left, Type_right)
{
    /* ... as you had it ... */
}

Example!(L, R) makeExample(L, R)(L x, R y)
{
    return new Example!(L, R)(x, y);
}

void main()
{
    auto foo = makeExample(1, 2);
    auto bar = makeExample(3, "baz");
}
----

Note that Example is not a type, but a template. That means, foo and bar have different types, because their types are different instantiations of the Example template. You can define a common interface or (possibly abstract) base class.

Great! Many thanks.