Delegate parameter name shadows type name

[Ali Çehreli via Digitalmars-d-learn]

This is something that surprised me in a friend's code.
(A "friend", hmmm? No, really, it wasn't me! :) )

// Some type of the API
struct MyType {
    int i;
}

// Some function of the API that takes a delegate
void call(void delegate(MyType) dlg) {
    dlg(MyType(42));
}

void main() {
    /* The programmer simply copied the delegate definition from
     * the function and used it as-is when passing a lambda: */
    call(delegate void(MyType) {
            /* WAT? Does the following really compile? After all,
             * MyType.i is NOT a static member! */
            if (MyType.i == 42) {
                // ...
            }
        });
}

I was surprised to see it compiled and worked but of course MyType at 
the lambda definition inside main() is not a type name, rather the 
parameter name. Surprising, but I think this is according to spec.

Ali