On Sunday, 16 April 2017 at 10:56:37 UTC, Era Scarecrow wrote:
On Saturday, 15 April 2017 at 11:10:01 UTC, Stefan Koch wrote:
It would requires an O(n^2) check per declaration.
Even it is never used.
which would make imports that much more expensive.
Seems wrong to me...
If you made a list/array of all the functions (based purely on
signatures) then sorted them, then any duplicates would be
adjacent. Scanning that list would be O(n-1).
This assumes it's done after all functions are scanned and
identified, doing it earlier is a waste of time and energy.
sorting has O(n^2) worst case complexity.
Therefore totaling to O(n^2) worst case again.
