On Friday, 21 April 2017 at 19:17:32 UTC, Adam D. Ruppe wrote:
Then realize that it does exactly the same thing when it is
inside a switch... it always breaks the innermost thing, which
happens to be this loop. (note that cases are not `breaked`,
the switch is.)
By coincidence I ran into this issue recently and assumed that
break should break the switch too (and I hadn't read the
boost::hana thread). Thanks for explaining, I thought it was
probably a compiler bug and hadn't gotten round to investigating
further.
So the compiler generates something like this:
int s = 0;
switch (s) {
case 0:
writeln("matched ");
default:
writeln("no match");
break;
}
If I compile the above I get:
Deprecation: switch case fallthrough - use 'goto default;' if
intended
IMO the compiler should issue this warning with the OP's code.
