On Tuesday, 2 May 2017 at 08:02:23 UTC, Suliman wrote:
On Saturday, 29 April 2017 at 08:57:09 UTC, Petar Kirov
[ZombineDev] wrote:
On Friday, 28 April 2017 at 18:08:38 UTC, H. S. Teoh wrote:
On Fri, Apr 28, 2017 at 04:42:28PM +0000, via
Digitalmars-d-learn wrote: [...]
writefln(text("%.", i, "f"), x);
[...]
There's no need to use text() here:
writefln("%.*f", i, x);
does what you want.
T
Thanks, I missed the fact that * could be used for specifying
the precision, in addition to the width.
I need co concatenate string with variant type (I am doing SQL
query).
What is the best way to put it? It's seems that if I am doing
simple `replace`
string sql = "..."
sql.replace(`37.72308`,
to!string(cargpspoint.lon)).replace(`55.47957`,
to!string(cargpspoint.lat))
I am loosing accuracy. Is there any better way?
I did:
sql_distance.replace(`37.72308`, format("%f",cargpspoint.lon))
It's seems that it's work ok. But is there any better way, or
it's ok?
