Re: Most convenient way to write a loop with fixed length and no need for the index?

[Ali Çehreli via Digitalmars-d-learn]

On 06/30/2017 12:44 AM, Martin Tschierschke wrote:

What do I have to do, to make this work?

iota(number).each!...command_x(a...);command_y(b...);command_z(c..))
                 ^^^^^?
how to write the lambda?

Similar to the ruby (1..number).each{ commands...}

Don't want to write the following, because the index i is not used
inside the loop
and this should be clear when reading it:

  for (i=0;i<number;i++){commands...}

or

  foreach(i;iota(number)){commands...}

Or is there something like number.times!{....} possible?

Seems easy to put together: :)

import std.stdio;

auto times(alias Func, T)(T number) {
    import std.range : iota;
    import std.algorithm : each;
    return number.iota.each!(_ => Func());
}

void foo() {
    writeln("foo");
}

void bar() {
    writeln("bar");
}

void main() {
    3.times!({ foo(); bar(); });
}

Ali