On Saturday, 5 August 2017 at 18:54:22 UTC, ikod wrote:
On Saturday, 5 August 2017 at 18:45:34 UTC, Simon Bürger wrote:
On Saturday, 5 August 2017 at 18:22:38 UTC, Stefan Koch wrote:
[...]
No, sometimes I want i to be the value it has at the time the
delegate was defined. My actual usecase was more like this:
void delegate()[3] dgs;
for(int i = 0; i < 3; ++i)
dgs[i] = (){writefln("%s", i); };
And I want three different delegates, not three times the
same. I tried the following:
void delegate()[3] dgs;
for(int i = 0; i < 3; ++i)
{
int j = i;
dgs[i] = (){writefln("%s", j); };
}
I thought that 'j' should be considered a new variable each
time around, but sadly it doesn't work.
Maybe std.functional.partial can help you.
Thanks. But std.functional.partial takes the fixed arguments as
template parameters, so they must be known at compile-time.
Anyway, I solved my problem already a while ago by replacing
delegates with custom structures which overload the
call-operator. I opened this thread just out of curiosity. Takes
a couple lines more but works fine.
