On Monday, 14 August 2017 at 15:11:35 UTC, Steven Schveighoffer
wrote:
On 8/14/17 10:57 AM, Carl Sturtivant wrote:
On Monday, 14 August 2017 at 14:49:57 UTC, Steven
Schveighoffer wrote:
On 8/14/17 10:36 AM, Carl Sturtivant wrote:
On Monday, 14 August 2017 at 14:24:40 UTC, Steven
Schveighoffer wrote:
I think what the docs mean is that as soon as an anonymous
union is present, you can't initialize anything further
than the first union field.
I understood that, hence my remark that "this is not
helpful".
OK. I thought you meant that the documentation is not helpful
enough to understand what it means.
So it seems I am forced to assign explicitly to each
member of the struct, an ugly process.
What is a nice way to solve this problem?
I think the only way to solve it is with a constructor:
this(int ival, double xval) { i = ival; x = xval; }
As I though I made clear, I don't want write assignments to
each variable in a 50 or 100 member struct from a library
when D could supply a better solution.
Sorry, I thought you meant to assign the fields manually
outside an initializer function.
I can print out such a struct using writeln, but can find no
way to use that text cleaned up in source code to create
such a struct. Is D completely deficient here?
Hm... have you tried named field initializers?
mess m = { i: 99, x: 3.14};
I could do that, but again it would involve finding the 50 or
100 names and writing text that looks quite like the text of
an assignment except using colon instead of equals. So just as
long and ugly.
Well, you only have to initialize the ones that aren't
defaulted. So in some use cases, this is hugely beneficial.
But it seems in your case, you want to intialize everything
explicitly (but only one member from each union).
Tried this, also works. Looks like you just have to name items
after the unions (i.e. when you are skipping members). Ugly,
but passable:
struct mess
{
union
{
int i;
string s;
}
double x;
int z;
}
mess s = {99, x: 3.14, 5};
-Steve
!
Agreed!