On Saturday, 26 August 2017 at 17:38:37 UTC, Vino.B wrote:
Hi,

Can some one provide me an example of how to wait for all the threads to be completed in a taskPool and then retrieve the data of all the threads together instead of getting the data of each threads(after successfully executed). For example, the below test program outputs only one string "Welcome" but not the string "Home".

import std.stdio;
import std.parallelism;

string Data;
auto Textarr = [ "Welcome", "Home" ];

string fn (string text)
{ return text; }

string Submain ()
{
 foreach ( i; taskPool.parallel(Textarr[0 .. $], 1))
   {
        auto Task = task(&fn, i);
        Task.executeInNewThread();
        auto TaskData = Task.workForce;
        Data ~= TaskData;
  }
  return Data;
}

void main ()
{
 Submain;
 writeln(Data[0 .. $]);
}

From,
Vino.B

Hi All,

Was able to find a solution, but the output writes additional empty lines., request your help on how to print without the empty lines.

Program:
import std.stdio;
import std.parallelism;
import std.algorithm;
import std.string;
string Data;
auto Textarr = [ "Welcome", "Home" ];
string endresult;
string fn (string text)
{ return text; }

void main ()
{
 string text;
 auto endresult = taskPool.workerLocalStorage(text);
 foreach ( i; parallel(Textarr[0 .. $], 1))
   {
        auto Task = task(&fn, i);
        Task.executeInNewThread();
        auto TaskData = Task.workForce;
        endresult.get ~= TaskData;
  }
  foreach (i; sums.toRange)
   { writeln(i); }
}

Output:
C:\Users\admin\Desktop\Script>rdmd test.d
Welcome
Home







C:\Users\admin\Desktop\Script>

Reply via email to