On 9/13/17 3:04 PM, nkm1 wrote:
Thank you. Now it is clear to me. The source of my confusion was that,
say, given a function:
inout(int*) foo(inout(int*) p)
as per table, combining (mutable) argument int* m with parameter
inout(int*) p would produce parameter type const(int*). But now I see
that the table deduces the common type of all parameters, not the common
type of a parameter and its argument (the documentation is kind of hard
to parse: "If such a match occurs, the inout is considered the common
qualifier of the matched qualifiers...").
Yeah, I should update that table and inout explanation...
-Steve
