19.09.2017 15:38, Steven Schveighoffer пишет:
On 9/19/17 8:01 AM, drug wrote:
I iterate over struct members and check against equality depending on
member type. is there more simple/cleaner/better way to achieve this
functionality? Especially without string mixins?
Why not just use tupleof directly instead of having to find the member
name and using mixins?
-Steve
Hmm, I'm sure I had tried it before and failed, but now I've managed to
do so and it's really simpler (https://run.dlang.io/is/GJkokW):
```
auto opEquals()(auto ref const(typeof(this)) rhs)
{
import std.math : approxEqual, isNaN;
import std.traits : isFloatingPoint, isIntegral;
static foreach(i; 0..this.tupleof.length)
{
{
alias FType = typeof(this.tupleof[i]);
// a field of this structure
auto tf = this.tupleof[i];
// a field of other structure
auto of = rhs.tupleof[i];
static if (isFloatingPoint!FType)
{
if (!tf.isNaN || !of.isNaN)
{
if (!approxEqual(tf, of))
return false;
}
}
else static if (isIntegral!FType)
{
if (tf != of)
return false;
}
else
static assert (0);
}
}
return true;
}
```
Thank you, Steven!
