Re: Is it possible to avoid call to destructor for structs?

[bitwise via Digitalmars-d-learn]

On Sunday, 24 September 2017 at 17:11:26 UTC, Haridas wrote:

In the following code, Bar is an element of struct Foo. Is there a way to avoid a call to ~Bar when ~Foo is getting executed?

Don't construct it to begin with.

struct Bar {
    import std.stdio : writeln;
    int a = 123;
    void boink() { writeln(a); }
    ~this(){ writeln("bar dtor"); }
}

struct Foo
{
    ubyte[Bar.sizeof] barBuffer;
    Bar* _bar = null;

    ref Bar bar()
    {
        import std.conv : emplace;

        if(!_bar) {
            _bar = cast(Bar*)barBuffer.ptr;
            emplace(_bar);
        }

        return *_bar;
    }
}

int main(string[] argv)
{
    Foo foo;
    foo.bar.boink();
    return 0;
}