On Sunday, 15 October 2017 at 08:47:42 UTC, Domain wrote:
void f(int i) { writeln("i"); }void f(E)(E e) if (is(E == enum)) { writeln("e"); } enum E { A } E e = E.A; f(e); // output i How can I overload with enum type?
I know I can do that with this: void f(T)(T i) if (is(T == int)) { writeln("i"); } But that looks strange.