On Wednesday, 6 December 2017 at 11:02:01 UTC, Jonathan M Davis
wrote:
If you only want one type, then given n that type; I'm pretty
sure that it would be
alias lambda = (int n) => n * n;
if you wanted an int. But if you want to do anything more
complicated with it, it would make more sense to just turn it
into a proper function template.
- Jonathan M Davis
Roight, I was more thinking along the lines of a little more
complicated I guess :)
i.e.:
template lambda(T)
if (isIntegral!T)
{
alias lambda = (T n) => n * n;
}
But you're right, if it gets more complicated a proper function
is probably better. Plus I just tried and it seems like you can't
really constrain a variable template anyway. Unless there's some
magic syntax I've overlooked in the docs.
Thanks!
Thanks!
