Re: Delegating constructor and call to super

[Mike Parker via Digitalmars-d-learn]

On Monday, 2 July 2018 at 09:42:36 UTC, Robert M. Münch wrote:

I think it's because of "If a constructor's code contains a 
delegate constructor call, all possible execution paths through 
the constructor must make exactly one delegate constructor call"

But, how am I supposed to call the super(int) consturctor and 
put my common initialization code into a delegating constructor?

class B {
        this(){ initialize(); }
        this(int a){super(a); initialize(); }
        private void initialize() { ... init some stuff for B ... 
}
}