On Saturday, 3 November 2018 at 13:20:22 UTC, Ecstatic Coder
wrote:
On Saturday, 3 November 2018 at 12:45:03 UTC, Danny Arends
wrote:
How can I convert a double value -12.000123456 to its string
value "-12.000123456", i.e. without loosing double-precision
digits ?
Specify how many digits you want with writefln:
writefln("%.8f", value);
Actually, what I need is the D equivalent of the default
ToString() function we have in Dart and C#.
I don't think it means what you think it means:
void main() {
double value = -12.000123456;
int precision = 50;
import std.stdio;
writefln("%.*g", precision, value);
import std.format;
string str = format("%.*g", precision, value);
writeln(str);
}
Prints:
-12.000123456000000743415512260980904102325439453125
-12.000123456000000743415512260980904102325439453125
That's not quite the -12.000123456 that you'd get from C#'s
ToString().
I mean a dumb double-to-string standard library conversion
function which returns a string including all the double
precision digits stored in the 52 significant bits of the
value, preferably with the trailing zeroes removed.
All of them? Most implementations of conversion algorithms
actually stop when it's "good enough". AFAIR, D doesn't even have
it's own implementation and forwards to C, unless that changed in
recent years.
