On Tuesday, 28 January 2020 at 07:36:25 UTC, Malte wrote:
I want to format an array using the %(...%) syntax. How can I
change the separator? I tried to use ? and add it as additional
parameter, but that doesn't seem to work on arrays:
import std;
void main()
{
writeln("This works:");
writefln("%,2?d", '_', 2000); // 20_00
auto vec = [1000, 2000, 3000];
writeln("This should fail (separator character expected)
but the ? is just ignored:");
writefln("%(%,2?d\t%)", vec); // 10,00 20,00 30,00
writeln("This throws:");
writefln("%(%,2?d\t%)", '_', vec); //
std.format.FormatException@/dlang/dmd/linux/bin64/../../src/phobos/std/format.d(2271): incompatible format character for integral argument: %(
}
I think I see why it's not working. Essentially, for each element
of vec, format is called with only that element as an argument.
Essentially, rather than:
foreach (e; vec)
writef("%,2?d\t", '_', e);
writeln();
You get:
foreach (e; vec)
writef("%,2?d\t", e);
writeln();
For whatever reason, it doesn't throw when missing an argument
for the separator - I'd say this is a bug
(https://issues.dlang.org/show_bug.cgi?id=20541).
For now, you can work around the issue this way:
import std.stdio : writefln;
import std.format : format;
import std.algorithm : map;
auto vec = [1000, 2000, 3000];
writefln("%-(%s\t%)", vec.map!(e => format!"%,2?d"('_', e)));
--
Simen