在 Sun, 12 Apr 2009 20:57:28 +0800，Michel Fortin
<michel.for...@michelf.com> 写道:
In D1 you had to write:
invariant
{
...
}
while in D2, to disabiguate with invariant being overloaded with
immutability you had to write:
invariant()
{
...
}
Now that the use of the invariant keyword in D2 has returned to its
single original meaning of class invariant, is there still a reason for
it to require an empty parenthesis? Should I fill a bug?
It will be good if it will be the same in both D1 and D2
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