Re: Fully dynamic d by opDotExp overloading

[davidl]

在 Fri, 17 Apr 2009 21:44:09 +0800，Leandro Lucarella <llu...@gmail.com>  
写道:

davidl, el 17 de abril a las 14:31 me escribiste:
After tweaking dmd a bit litte, i get the dotexp overloading work.
The following is the test code:
import std.stdio;
class c
{

    B opDotExp(char[] methodname,...)
    {
        writefln("god it works ", methodname);
      return new B();
    }
    void opAdd(int j)
    {

    }
    void test()
    {
    }
}

class a:c
{

}

class B
{
  int i;
  B opAssign(int k){
    i=k;
    return this;
  }
}

char[] v1;

void func(char[] v, ...){}

void main()
{
   a v=new a;
   v.test();
   v.dynamicmethod(3,4);
   //v.qq = 5;
   writefln((v.qq = 5).i);
}

it generates the output:
god it works dynamicmethod
god it works qq
5

Any comments? Do you like this feature?

This is awsome indeed. I'd love to see it in the specs. The suggestion of
making opDotExp a template it's good one too. I guess that now that opDot
is replaced by alias this, opDot can be used for this instead of  
opDotExp.

I don't fully understand the example though. In writefln((v.qq = 5).i),
how is that B.i is assigned to 5 if the opDotExp("qq", 5) don't propagate
the 5 to the new B()?

Thanks for the great job.


Thanks, the example here v.qq returns a B object, and then the assignment  
kicks in, therefore it calls B.opAssign(5), thus the i member of that B  
instance is 5.


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