On 26 November 2012 18:49, jerro <a...@a.com> wrote:
> How can I fix the template declaration to not error in that case?
>>
>
> If you want to have a template parameter that can be anything, including a
> a symbol or a built in type, you can use this ugly workaround:
>
> template foo(bar...) if(bar.length == 1)
> {
> enum foo = 1;
> }
>
Ahhhhh, that explains why 90% of std.traits is written in that super-weird
way! I always wondered what that was all about.
When you say 'anything' though, does that include alias parameters? Will
bar[0] be the equivalent of template foo(alias bar) if called with a symbol?
