On 01/03/2013 01:52 PM, Jason House wrote:
On Thursday, 3 January 2013 at 05:56:27 UTC, Timon Gehr wrote:
On 01/03/2013 12:48 AM, Jason House wrote:
...
ref int bar()
{
int i = 7;
return foo(i);
}
If @safe, this code will not compile.
Error: foo may return a local stack variable
Since "i" is a local variable, "foo(i)" might return it.
ref int baz(int i)
{
return foo(i);
}
This function is fine. "i" is an input argument so "foo(i)" is
considered to be equivalent to an input argument.
Those two cases are pretty much the same.
If what I suggest is done, they must be differentiated. If you replace
"return foo(i)" with "return i", the compiler will already issue an
error for the local variable case.
Obviously _both_ examples result in memory corruption. i is not a ref
parameter.
