Re: asm code and an inout function argument

[Tim Matthews]

On Fri, 15 May 2009 22:29:07 +1200, Robert Fraser  
<fraseroftheni...@gmail.com> wrote:

Vladimir A. Reznichenko wrote:
I have a function:
 void test (inout uint a)
{
        asm
        {
                mov a, 0x25;
        }
}
 The trouble is that the function's call doesn't change the a variable.
Any ideas?

Inout variables are pointers.


Why is it 'inout' and not 'ref' ?