Hello, I've two simple questions:

1. I have a structure:

struct Foo
{
  public int bar() const {return 0;}
  public int bar() immutable {return 1;}
}

How can I get immutable bar address?

When I've wrote next code I've got a const bar address. Is it a bug?

void main()
{
    immutable Foo boo;
    int delegate() immutable dg = &boo.bar;
}

Next question:
If I write ั‚ัƒั‡ะต code, it'll be builded successfully

void main()
{
    foreach(cur; __traits(getOverloads, Foo, "bar"))
    {
        void* p = &cur;
        writeln(cur); //prints a function pointer.
    }
}

If I change protection of bar to export I've got a error:

struct Foo
{
  export int bar() const {return 0;}
  export int bar() immutable {return 1;}
}

void main()
{
    foreach(cur; __traits(getOverloads, Foo, "bar"))
    {
        void* p = &cur; //Error: need 'this' to access member bar
        writeln(cur);
    }
}

How should it be?

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